Home
Class 12
CHEMISTRY
At 298 K, 1000 cm^(3) of a solution coco...

At 298 K, `1000 cm^(3)` of a solution cocontaining 4.34 g solute shows osmotic pressure of 2.55 atm. What is the molar mass of solute ? `(R=0.0821Latm K_(-1)mol^(-1))`

A

`41.64 g mol^(-1)`

B

`82.73 g mol^(-1)`

C

`58.31 g mol^(-1)`

D

`91.65 g mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`pi=CRT=(w)/(Mw)xx(1000)/(v(mL))xxRxxT`
`2.55=(4.34)/(Mw)xx(1000)/(1000)xx0.082xx298`
`M_(w)=41.64`
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

100 mg of a protein was disoved in just enough water to make 10 mL of the solution. If the solution has an osmotic pressure of 13.3 mm Hg at 25^(@)C , what is the mass of prtein (R=0.0821 L atm mol^(-1)K^(-1))

A decinormal solution of NaCl exerts an osmotic pressure of 4.6 atm. at 300 K. Calculate its degree of dissociation. (R=0.082Latm.K^(-1)mol^(-1))

Three grams of non - volatile solute whenn dissolved in a litre of water shows an osmotic pressure of 2 bar at 300K. Calculate the molar mass of the solute . (R = 0.083 L bar K^(-1) mol^(-1) ) .

The osmotic pressure of 0.2 molar solution of urea at 300 K(R = 0.082) litre atm mol^(-1)K^(-1) is