Home
Class 12
CHEMISTRY
Dissolving 120g of urea (Mw = 60) in 100...

Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:

A

1.78 M

B

2.00 M

C

2.05 M

D

2.22 M

Text Solution

Verified by Experts

The correct Answer is:
C
`m=(1000M)/(1000d-MMw)`
`(120)/(60)xx(1000)/(1000)=(1000M)/(1000xx1.5-M(60))`
`2.30xx1000-120M=1000M`
`M=(2.30xx1000)/(1120)=2.05`
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

Dissolving 120g of urea (mol wt = 60) in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is

Dissolving 120 g of urea (molecular mass = 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is :

Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of density 1.158g//mL . The molarity of the solution is

Dissolving 180 g of glucose (mol.w.t. 180) in 1000g of water gave a solution of density 1.15 g//mL . The molarity of the solution is

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g // mL . The molarity of the solution is: