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A solution of substance containing 1.05 ...

A solution of substance containing `1.05` g per 100 mL was found to be isotonic with `3%` glucose solution . The molecular mass of the substance is :

A

31.5

B

6.3

C

630

D

63

Text Solution

Verified by Experts

The correct Answer is:
D
`(1.05)/(Mw)xx10=(3)/(180)xx10`
`Mw=1.05xx60=63`
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