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The correct expression for Arrehenius eq...

The correct expression for Arrehenius equation :-

A

`lnk=lnA-(E)/(RT)`

B

`Ke^(-E//RT)=A`

C

log k=log A `-2.303(E)/(RT)`

D

`K=A^(-1)e^(-E//RT)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K=_(Ae)(Ea)/(RT)`
`In " K" =In" A"-(Ea)/(RT)`
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