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Rate of formation SO(3) in this reaction...

Rate of formation `SO_(3)` in this reaction is `1.6xx10^(-3)kg//min`
`2SO_(2)+O_(2)to2SO_(3)` then rate at which ` SO_(2)` reacts is :-

A

`1.6xx10^(-3) kg//mi n^(-1)`

B

`8xx10^(-4) kg//mi n^(-1)`

C

`3.2xx10^(-3)kg mi n^(-1)`

D

`1.28xx10^(-3)kg mi n^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(dSO_(3))/(dt)=1.6xx10^(-3) Kg//min`
`=(1.6xx10^(-3)1000)/(80)mol//min`
`(dSO_(2))/(2dt)-(-dO_(2))/(dt)=(dSO_(3))/(2dt)`
`(-dSO_(2))/(dt)=(1.6)/(80)mol//min`
`(1.6)/(80)xx64xx10^(-3)kg//mol`
`=1.28xx10^(-3)mol//min`
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