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For a reaction rate =K(A)^(1//2)(B)^(2)....

For a reaction rate `=K(A)^(1//2)(B)^(2)`. If concentration of A amd B are increased by factor of 4 and 2 respectively then rate is changed by the fraction :-

A

4

B

6

C

8

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`r=K(4)^(1//2)(2)^(2)`
`r=2xx2xx2rArr8 "times"`
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