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For the reaction, 2N(2)O(5)to4NO(2)+O(2)...

For the reaction, `2N_(2)O_(5)to4NO_(2)+O_(2)` rate and rate constant are `1.02xx10^(-4) M sec^(-1)` and `3.4xx10^(-5)sec^(-1)` respectively, the concentration of `N_(2)O_(5)`, at that time will be

A

1.732 M

B

3M

C

`1.02xx10^(-4)` M

D

`3.5xx10^(5)M`

Text Solution

Verified by Experts

The correct Answer is:
B
`r=k[N_(2)O_(5)]^(1)`
`1.02xx10^(4)=3.4xx10^(-5)[N_(2)O_(5)]`
`rArr[N_(2)O_(5)]=(1.02xx10^(-4))/(3.4xx10^(-5))=3M`
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