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For the decomposition, N(2)O(5)(g) rar...

For the decomposition,
`N_(2)O_(5)(g) rarr N_(2)O_(4)(g) + 1//2O_(2)(g)`, the initial pressure of `N_(2)O_(5)` is `114 mm` and after `20 sec`, the pressure of reaction mixture becomes `133 mm`.
Calculate the rate of reaction in terms of :
(a) change in pressure `sec^(-1)` and
(b) change in molarity `sec^(-1)`. Given that reaction is carried out at `127^(@)C`.

A

`1.25xx10^(-3) atm sec^(-1)`

B

`2.5xx10^(-3) atm sec^(-1)`

C

`9.5xx10^(-1) atm sec^(-1)`

D

`4.75xx10^(-1) atm sec^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(N_(2)O_(5),to,N_(2)O_(4),+,(1)/(2)O_(2)),(114.p,,p,,(1)/(2)p):}`
`P_(T)=114+(P)/(2)=133rArrp=38`
`K=(2.303)/(20)"log"((114)/(76))`
`K(Pt)=2.07xx10^(-3)`at m `sec^(-1)`
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