Home
Class 12
CHEMISTRY
Given the standard electrods potential ...

Given the standard electrods potential
`K^(+)//K=-3.02V`
`Cu^(+2)//Hg=+0.34V`
`Hg^(+2)//Hg=0.92`
`Cr^(+3)//Cr=-0.74V`
Decreasing order of reducing power of these element is

A

`agtbgtcgtd`

B

`agtdgtcgtb`

C

`agtdgtbgtc`

D

`cgtbgtdgta`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

Given standard electrode potentials K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V , Hg^(2+)|Hg=0.79V Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V Arrange these metals in their increasing order of reducing power.

Given the standard electrode potentials, K^(+) | K = -2.93 V , Ag^(+) | Ag = 0.80 V , Hg_(2)^(2+) | Hg = 0.79 V , Mg_(2)^(2+) | Mg = -2.73 V , Cr_(2)^(3+) | Cr = -0.74 V . Arrange these metals in increasing order of their reducing power.