Home
Class 12
CHEMISTRY
Pt|H(2)(1 atm )|H^(+)(0.001M)||H^(+)(0.1...

`Pt|H_(2)(1 atm )|H^(+)(0.001M)||H^(+)(0.1M)|H_(2)(1atm)|Pt` what will be the value of `E_(cell)` for this cell

A

0.1182V

B

`-0.1182V`

C

0.0591 V

D

`-0.0591 V`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos
  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

The observed emf of the cell, Pt|H_(2) ("1 atm")|H^(+)(3xx10^(-4) M)||H^(+) (M_(1))|H_(2) ("1 atm")|Pt is 0.154 V. Calculate the value of M_(1) and pH of cathodic solution.

The pH of LHE in the following cell is : Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt E_(cell)=0.295V .

The electrochemical cell is set up as pt, H_(2)(1 atm)| HCl (0.1 M)|| CH_(3)COOH (0.1 M) | H_(2) (1 atm) , pt. The emf of the cell is (Ka =10^(-3) xx 1.8 )

The emf of the following cell is observed to be 0.118V at 25^(@)C . [Pt,H_(2)(1atm)|HA(100mL 0.1M||H^(o+)(0.1M)|H_(2)(1atm)|Pt] a. If 30mL of 0.2M NaOH is added to the negative terminal of battery, find the emf of the cell. b. If 50mL of 0.2 M NaOH is added to the negative terminal of battery, find the emf of teh cell.

An electrochemical cell is shown below Pt, H_(2)(1 "atm")|HCl(0.1 M)|CH_(3)COOH(0.1 M)|H_(2)(1 "atm") , The emf of the cell will not be zero, because

For the cell Pt_((s)), H_(2) (1 atm)|H^(+) (pH=2)||H^(+) (pH=3)|H_(2) (1atm),Pt The cell reaction is

Consider the cell : Pt|H_(2)(p_(1)atm)|H^(o+)(x_(1)M) || H^(o+)(x_(2)M)|H_(2)(p_(2)atm)Pt . The cell reaction be spontaneous if