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CH(3)-underset(CH(3))underset(|)overset(...

`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH-CH_(3)overset(H-Cl)(to)` ?

A

`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-underset(Cl)underset(|)(CH)-CH_(3)`

B

`CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-CH-underset(CH_(3))underset(|)(CH_(2))-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-underset(Cl)underset(|)CH=CH_(2)-CH_(3)`

D

`CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`

Text Solution

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The correct Answer is:
A
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