n-propyl bromide reacts with aqueous KOH to form:-

Options

A. Propane
B. Propene
C. Propyne
D. Propanol

Answer

To solve the problem of what n-propyl bromide reacts with aqueous KOH to form, we can follow these steps:

### Step 1: Understand the Reactants
- **Identify n-propyl bromide**: The chemical structure of n-propyl bromide is CH3-CH2-CH2-Br. It is a primary alkyl halide.

### Step 2: Identify the Reaction Type
- **Aqueous KOH**: When n-propyl bromide reacts with aqueous KOH, it typically undergoes a substitution reaction. The hydroxide ion (OH-) from KOH will replace the bromine atom (Br-) in n-propyl bromide.

### Step 3: Write the Reaction
- **Substitution Reaction**: The reaction can be represented as follows:
\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + \text{KOH (aq)} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} + \text{KBr} \]
- Here, Br is replaced by OH, resulting in the formation of propanol (CH3-CH2-CH2-OH) and potassium bromide (KBr) as a byproduct.

### Step 4: Identify the Product
- **Final Product**: The product formed is propanol, specifically 1-propanol (or n-propanol), which is an alcohol.

### Conclusion
- The final answer to the question is that n-propyl bromide reacts with aqueous KOH to form **propanol**.

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