Identify the end product :
`CH_(3)CH_(2)CH_(2)CHOoverset(Ammonical AgNO_(3))(to)Xoverset(NaHCO_(3))(to)Yunderset(Delta)overset(NaOH+CaO)(to)Z`

Options

A. `CH_(3)-CH_(2)CH_(2)-COOH`
B. `CH_(3)-CH_(2)-CH_(2)-CH_(3)`
C. `CH_(3)-CH_(2)-COOH`
D. `CH_(3)-CH_(2)-CH_(3)`

Answer

To identify the end product of the given reaction sequence, we will analyze each step carefully.

### Step-by-Step Solution:

1. **Identify the Starting Compound:**
The starting compound is butanal, represented as CH₃CH₂CH₂CHO.

2. **Reaction with Ammonical AgNO₃:**
Ammonical AgNO₃ is known as Tollens' reagent, which is used to oxidize aldehydes.
- The aldehyde group (CHO) in butanal will be oxidized to a carboxylic acid (COOH).
- Therefore, after this reaction, the product X will be butanoic acid:
\[ X = CH₃CH₂CH₂COOH \]

3. **Reaction with NaHCO₃:**
Sodium bicarbonate (NaHCO₃) is a weak base and will react with the carboxylic acid to form a carboxylate salt.
- The reaction will yield the butanoate ion (the conjugate base of butanoic acid):
\[ Y = CH₃CH₂CH₂COO^- \]

4. **Decarboxylation Reaction with NaOH and CaO:**
The combination of NaOH and CaO can lead to decarboxylation, which removes the carboxyl group (COO⁻) from the carboxylate ion.
- The decarboxylation of butanoate ion will yield butyl anion (CH₃CH₂CH₂⁻).
- After protonation, this anion will convert into butane:
\[ Z = CH₃CH₂CH₃ \]

5. **Final Product:**
The final product Z is butane (C₄H₁₀), which is also known as n-butane.

### End Product:
The end product of the reaction sequence is **butane (C₄H₁₀)**.

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