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A wire of length l, area of cross sectio...

A wire of length l, area of cross section A and Young’s modulus of elasticity Y is stretched by a longitudinal force F. The change in length is `Deltal` Match the following two columns.

Text Solution

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The correct Answer is:
A-P,Q;B-P;C-R,S;D-R
`lDelta=(Fl)/(AY)"and stress"=(F)/(A)`
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