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In the figure shown below, the charge on...

In the figure shown below, the charge on the left plate of the `10muF` capacitor is `-30muF`. The change on the right plate of the `6muF` capacitor is:

A

`+18muC`

B

`-18muC`

C

`-12muC`

D

`+12muC`

Text Solution

Verified by Experts

The correct Answer is:
A
By division of charge on capacitor in parallel,
. `q=+18muC`.
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