Chlorophyll present in green leaves of plants absorbs light at `4.620xx10^(14)Hz`. Calculate the wavelength of radiation in nanometer. Which part of the electromagnetic spectrum does it belong to?

Explanation

Wavelength, `lambda=(c)/(v)`
Given, frequency `v=4.620xx10^(14)Hz` or `4.620xx10^(14)s^(-1)`
`lambda=(c)/(v)=(3xx10^(8)ms^(-1))/(4.620xx10^(14)s^(-1))`
`=0.6494xx10^(-6)m`
`=649.4m [because 1nm=10^(-6)m]`
Thus, it belongs to visible region.