A graph of x versus t is shown in figure. Choose correct alternative from below.

Options

A. The particle was released from rest at `t = 0`
B. At B, the acceleration `a gt 0`
C. Average velocity `a gt 0`
D. The speed at D exceeds that at E

Answer

A, C, D

Explanation

As per the diagram, at point A the graph is parallel to time axis hence, `v = (dx)/(dt) = 0`. As the starting point is A hence, we can say that the particle is starting from rest.
At C, the graph changes slope, hence, velocity also changes. As graph c is almost parallel to time axis hence, we can say that velocity vanishes.
As direction of acceleration changes hence, we can say that it may be zero in between.
From the graph it is clear that
`|"slope at D"| gt |"slope at E"|`
Hence, speed at D will be more than at E.