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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.

A

0.1 s

B

0.11 s

C

1.0 s

D

0.01 s

Text Solution

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The correct Answer is:
2
`"Average value"=(2.63+2.56+2.42+2.71+2.80)/(5)`
`=2.62 sec.`
`"Now " |/_\T_(1)|=2.63-2.62=0.01`
`|/_\T_(2)|=2.62-2.56=0.06`
`|/_\T_(3)|=2.62-2.42=0.20`
`|/_\T_(4)|=2.71-2.62=0.09`
`|/_\T_(5)|=2.80-2.62=0.18`
Mean absolute error
`/_\T=(|/_\T_(1)|+|/_\T_(2)|+|/_\T_(3)|+|/_\T_(4)|+|/_\T_(5)|)/(5)`
`/_\T=(0.54)/(5)=0.108=0.11sec.`
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