The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity `(take g=10ms^(-2))` The maximum height will be decreased by:

Options

A. `11%`
B. `10%`
C. `9%`
D. `12%`

Answer

3

Explanation

`H=(u_(y)^(2))/(2g)`
H'`=(u_(y)^(2))/(2((11g)/(10)))`
`(H)/(H')=(11)/(10)`
H'`=(11)/(10)H`
% decrease in height
`=(H-H')/(H)xx100`
`=(100)/(11)~=9%`