A body of weight 2 kg is suspended as shown in the figure. The tension `T_(1)` in the horizontal string (in kg wt ) is

Options

A. `2//sqrt(3)`
B. `sqrt(3)//2`
C. `2sqrt(3)`
D. 2

Explanation

T sin 30 2kg wt `rArr` T = 4kg wt

`T_(1)=T cos 30^(@) =4 cos 30^(@) = 2sqrt(3)`
and T `sin 30^(@) =2g`