Figure shown a man standing stationary with respect to a horizontal converyor belt that is accelerationg with `1m//s^(-2)` . What is the net force on the man?If the coefficient of ststic friction between the man's shoes and the belt is `0.2` upto what maximum acceleration of the belt can the man continue to be stationary relative to the belt? Mass of the man`= 65kg (g =9.8m//s^(2))`

Options

A. `1.25ms^(-2)`
B. `1.96^(-2)`
C. `2.5ms^(-2)`
D. `3.6ms^(-2)`

Explanation

[1]
As the man is standing stationary w.r.t. the horizontal conveyor belt, he is also accelerating at 1 `ms^(-2)`, the acceleration of the belt Thus, Acceleration of the man , M `= 65` Kg
Therefore, net force on the man, Ma `65xx1=65` N
The limiting friction between the shoes of the man and the is given by
F`=muMg=0.2xx65xx9.8N`
If the man can remain stationary upto an acceleration say a then
Ma `=F`
or a `=(F)/(M)=(0.2xx65xx9.8)/(65)=1.96 ms ^(-2)`