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When the KE of a particle is increased b...

When the KE of a particle is increased by 300%, the momentum of the body si increased by :

A

`100%`

B

`150%`

C

`sqrt(300%)`

D

`175%`

Text Solution

Verified by Experts

[1]
Let initial energy `E_(1)=E`
final KE, `E_(2)=E+300%` of E= 4E
As P `propsqrt(E)rArr(P_(2))/(P_(1))=sqrt((E_(2))/E_(1))=sqrt((4E)/(E))=2`
`rArrP_(2)=2P_(1)rArrP_(2)=P_(1)+100%of P_(1)`
i.e. momentum will increase by `100%`
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