Find the following integrals: `int(x+3)/(sqrt(5-4x+x^2))dx`

Explanation

Given `I=∫(x+3)/sqrt(x^2−4x+5
)dx`

Putting `x+3=Ad/dx​*(x^2−4x+5)+B`

=`x+3=A(2x−4)+B`

=`x+3=2Ax−4A+B`

On comparing both sides we get

`2A=1`

`−4A+B=3`

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