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For the reactions A hArr B, K(c ) =1 ...

For the reactions
`A hArr B, K_(c ) =1`
`B hArr C, K_(c)=2`
`C hArr D, K_(c)=3`
`K_(c)` for the reaction `A hArr D` is

A

`5`

B

6

C

15

D

1

Text Solution

Verified by Experts

The correct Answer is:
B
`([B])/([A])=1,([C])/([B])=2,([D])/([C])=3.`
On multiplying the three, we get
`([D])/([A])=1xx2xx3=6`
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