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The vapour density of Pcl(5) is 104.16 b...

The vapour density of `Pcl_(5)` is `104.16` but when heated to `230^(@)C`, its vapour density is reduced to `62`. The degree of dissociation of `PCl_(5)` at `230^(@)C` is …………

A

`6.8%`

B

`68%`

C

`46%`

D

`64%`

Text Solution

Verified by Experts

The correct Answer is:
B
`PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`
Here `y=2`
`x=(D-d)/(d(y-1))=(104.16-62)/(62)`
`=0.68=68%`
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