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For the equilibrium 2H(2)O(g) hArr 2H(2)...

For the equilibrium `2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g)`, equilibrium constant is `K_(1)`
For the equilibrium `2CO_(2)hArr 2CO(g)+O_(2)(g) `, equilibrium constant is `K_(2)`
The equilibrium constant for `:`
`CO_(2)(g)+H_(2)(g)hArr CO(s)+H_(2)O(g)` is `:`

A

`K_(1)K_(2)`

B

`(K_(1))/(K_(2))`

C

`sqrt((K_(1))/(K_(2)))`

D

`sqrt((K_(2))/(K_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
D
`2H_(2)O(g)hArr 2H_(2)(g)+O_(2)(g),K_(1)`
`H_(s)(g)+(1)/(2)O_(2)(g)hArr H_(2)O(g)K=(1)/(sqrt(K_(1)))`
`CO_(2)(g)hArr CO(g)+O_(2)(g),K'=sqrt(K_(2))`
If eqm. Constant for the reaction
`CO_(2)(g)+H_(2)(g)hArr CO(g)+H_(2)(g)+(1)/(2)O_(2)(g)` is `K''`, then
`K''=KxxK'=sqrt((K_(2))/(K_(1)))`
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