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In Figure, line l is the bisector of ang...

In Figure, line `l` is the bisector of angle `A` and `B` is any point on `l` . `B P` and `B Q` are perpendiculars from `B` to the arms of `Adot` Show that : `A P B~=A Q B` `B P=B Q` or `B` is equidistant from the arms of `/_A` . Figure

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Verified by Experts

Given- `/_1=/_2`
`In /_AQB and /_APB`
`/_1=/_2`(given)
`AB=AB`(common)
`/_BQA=/_BPA`(each 90)
`/_AQB cong /_APB`(AAS)
`BQ=BP`.
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RD SHARMA-CONGRUENT TRIANGLE -All Questions
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