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If the bisectors of the base angles of a triangle enclose an angle of `135^0,` prove that the triangle is a right triangle.

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To prove- `/_ABC` is right angled
`/_OBC=/_B/2`
`/_OCB=/_C/2`
`In /_BOC`
`/_BOC+/_OBC+/_OCB=180^@`
`135^@+/_B/2+/_C/2=180^@`
`1/2(/_B+/_C)=45^@`
`/_B+/_C=90^@`
...
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