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If `A B C` is an isosceles triangle such that `A B=A C` and `A D` is an altitude from `A` on `B C` . Prove that (i) `/_B=/_C` (ii) `A D` bisects `B C` (iii) `A D` bisects `/_A`

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` In /_ADC and /_ABD`
`AB=AC`(given)
`/_ADB=/_ADC(each 90^@)`
`AD=AD`(common)
`/_ADc cong /_ABD(RHS)`
`/_B=/_C,BD=CD`
`/_BAD=/_CAD`.
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