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Prove that the sum of the three angles o...

Prove that the sum of the three angles of a triangle is `180^0dot`

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To prove that the sum of the three angles of a triangle is \(180^\circ\), we can follow these steps: ### Step-by-Step Solution: 1. **Draw Triangle**: Start by drawing a triangle \(ABC\). Label the angles as follows: - Angle at vertex \(A\) as \(\angle A\) - Angle at vertex \(B\) as \(\angle B\) - Angle at vertex \(C\) as \(\angle C\) ...
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Knowledge Check

  • The sum of three altitudes of a triangle is

    A
    equal to the sum of three sides
    B
    less than the sum of sides
    C
    greater than the sum of sides
    D
    twice the sum of sides
  • The sum of three altitudes of a triangle is

    A
    equal to the sum of three sides
    B
    less than the sum of sides
    C
    greater then the sum of sides
    D
    twice the sum of sides.
  • Similar Questions

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    Theorem 6.7 : The sum of the angles of a triangle is 180º

    Which of the following statements are true (T) and which are false (F): Sum of the three angles of a triangle is 180^0 A triangle can have two right angles. All the angles of a triangle can be less than 60^0 All the angles of a triangle can be greater than 60^0 All the angles of a triangle can be equal to 60^0 A triangle can have two obtuse angles. A triangle can have at most one obtuse angles. In one angle of a triangle is obtuse, then it cannot be a right angled triangle. An exterior angle of a triangle is less than either of its interior opposite angles. An exterior angle of a triangle is equal to the sum of the two interior opposite angles. An exterior angle of a triangle is greater than the opposite interior angles