In a ` A B C ,` if `2/_A=3/_B=6/_C ,` determine `/_A ,/_B` and `/_Cdot`

Explanation

To solve the problem, we need to determine the angles \( \angle A \), \( \angle B \), and \( \angle C \) in triangle \( ABC \) given the relationship \( \frac{2}{\angle A} = \frac{3}{\angle B} = \frac{6}{\angle C} \).

### Step-by-Step Solution:

1. **Set Up the Relationship**:
Let \( \frac{2}{\angle A} = \frac{3}{\angle B} = \frac{6}{\angle C} = k \) (where \( k \) is a constant).
From this, we can express the angles in terms of \( k \):
\[
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