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If p=2-a , prove that a^3+6a p+p^3-8=0...

If `p=2-a ,` prove that `a^3+6a p+p^3-8=0`

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"
Given `p=2-a `
We have to prove that `a^3+6a p+p^3-8=0`
Substitute `p=2-a ` in `a^3+6a p+p^3-8=0`
`=>a^3+6a (2-a)+(2-a)^3-8=0`
`=>a^3+12a-6a^2+8-a^3-12a+6a^2-8=0`
`=>0=0`
Hence proved."
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