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Factorize the following expression : `(2x-3y)^3+(4z-2x)^3+(3y-4z)^3`

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If `a+b+c=0`, then `a^3+b^3+c^3=3abc`.
`(2x-3y)^3+(4z-2x)^3+(3y-4z)^3=3(2x-3y)(4z-2x)(3y-4z)`
`:.(2x-3y)^3+(4z-2x)^3+(3y-4z)^3=6(2x-3y)(2z-x)(3y-4z)`
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