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In a ` A B C ,` it is given that `A B=A C` and the bisectors of `/_B` and `/_C` intersect at `O ,` If `M` is a point on `B O` produced, prove that `/_M O C=/_A B Cdot`

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In AABC, we have
`AB = AC`
→`/_C = /_B`
= `1/2 /_C = 1/2 /_B`
⇒ ` /_OCB= /_OBC` ...(i)
In `/_\OBC`, we have
`/_MOC= /_OBC+ /_OCB`
⇒ `/_MOC= /_OBC+ /_OBC `[Using (i)]
⇒`/_MOC = 2/_OBC = /_ABC`.
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