`A B C` is a triangle in which `/_B` =2 `/_CdotD` is a point on `B C` such that `A D` bisects `/_B A C` and `A B=C D` . Prove that `/_B A C=72^0dot`

Explanation

To solve the problem, we need to prove that the angle \( \angle BAC = 72^\circ \) given the conditions of the triangle \( ABC \) and the point \( D \) on \( BC \).

### Step-by-Step Solution:

1. **Understand the Given Information:**
- We have triangle \( ABC \) where \( \angle B = 2 \angle C \).
- Point \( D \) is on line segment \( BC \) such that \( AD \) bisects \( \angle BAC \).
- It is given that \( AB = CD \).
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