Electronegativity of carbon atoms depend...

Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative ?

`CH_(3) - CH_(2) - .^(**)CH_(2) - CH_(3)`

`CH_(3) - .^(**)CH = CH - CH_(3)`

`CH_(3) - CH_(2) - C -= .^(**)CH`

`CH_(3) - CH_(2) - CH = .^(**)CH_(2)`

Text Solution

Verified by Experts

The correct Answer is:

Electrongativity of carbon atom depends on their state of hybridisation. More s-character more the electronegativity.
`{:(sp^(3),lt,sp^(2),lt,sp,),(25% s,,33% s,,50% s,):}`
Thus, sp-carbon has the highest electronegativity, i.e., option (c) `(CH_(3) - CH_(2) - C -= .^(**)CH)` is correct

Topper's Solved these Questions

ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES
NCERT EXEMPLAR|Exercise Short Answer type question|27 Videos
ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES
NCERT EXEMPLAR|Exercise Matching the columns|5 Videos
HYDROGEN
NCERT EXEMPLAR|Exercise LONG ANSWER TYPE QUESTIONS|8 Videos
REDOX REACTIONS
NCERT EXEMPLAR|Exercise LONG ANSWER TYPE QUESTIONS|6 Videos

Electronegativity of carbon atoms depends upon their state of hybrisation. In which of the following compounds, the carbon marked with asterisk is most electronagative ?

`CH_(3)-CH_(2)-^(**)CH_(2)-CH_(3)`

`CH_(3)-^(**)CH=CH-CH_(3)`

`CH_(3)-CH_(2)-C equiv^(**)CH`

`CH_(3)-CH_(2)-CH=^(**)CH_(2)`

Electronegativity of carbon atoms depends upon their state of hybridisation in which of the following compounds the carbon marked asterisk, is most electronegative ?

`CH_(3)-CH_(2)-CH_(2)-CH_(3)`

`CH_(3)-CH=CH-CH_(3)`

`CH_(3)-CH_(2)-C-=CH`

`CH_(3)-CH_(2)-CH=CH_(2)`

In which of the following compounds the carbon marked with asterisk is expected to have greatest positive charge ?

`.^(**)CH_(3)-CH_(2)-Cl`

`.^(**)CH_(3)-CH_(2)-Mg^(+)Cl^(-)`

`.^(**)CH_(3)-CH_(2)-Br`

`.^(**)CH_(3)-CH_(2)-CH_(3)`