Prove that: 18x [7+ (-3)] = [18x7] + [18x (-3)]

Verify that:- 18x [7+ (-3)] = [18x7] + [18x (-3)]

18xx[7+(-3)]=[18xx7]+[18xx(-3)]

(2x)/(3)=18

.Verify the following: 18times[7+(-3)],=[18times 7]+[18times(-3)]

If a=sin\ pi/18 sin\ (5pi)/18 sin\ (7pi)/18, and x is the solution of the equation y=2[x]+2 and y=3[x-2], where [x] denotes the integral part of x then a= (A) [x] (B) 1/[x] (C) 2[x] (D) [x]^2

Divide 18x^(4) - 27 x^(3) + 6x by 3x.

Solve |5x -7| lt -18

Factorise the x ^(2) + 18x + 65