The charge on a capacitor becomes `(1)/(n)` times of its initial value in time `t` ,when it discharges through,a circuit with time constant `T` .The value of t is

The charge on a capacitor decrease eta time in time t , when it discharging through a circuit with a time constant tau

A capacitor C is connected to two equal resistances as shown in the figure. Consider the following statemets i. At the time of charging of capacitor time constant of the circuit is 2CR ii. At the time of discharging of the capacitor the time constant of the circuit is CR iii. At the time of discharging of the capacitor the time constant of the circuit is 2CR iv At the time of charging of the capacitor the time constant of the circuit is 2CR

LetC be the capacitance of a capacitor discharging through a resistor R. Suppose t_1 is the time taken for the energy stored in the capacitor to reduce to half its initial value and t_2 is the time taken for the charge to reduce to one-fourth its initial value. Then the ratio t_1//t_2 will be

The value of displacement current at t=1 time constant is

In the circuit shown in fig. when the switch is closed, the capacitor charges with a time constant

During the decay of current in an LR circuit, if the current falls to eta times the intial value in time T , then determine the value of time constane.

Find (a) equivalent time constant, (b) charge on capacitor in terms of time t.

The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure. What is the value of current at t=4s ?