A person in a lift which ascends up with acceleration 10m/s2 drops a stone from a height 10m. Time of descent is A) 1 sec B) 2 sec C) 1.5 sec D) 3 sec

" A person in a lift which ascends up with acceleration "10m/s^(2)" drops a stone from a height "10m" .Time of descent is "

A lift is moving up with an acceleration of 3.675 m//sec_(2) . The weight of a man-

A balloon a ascending vertically with an acceleration of 0.4m//s^(2) . Two stones are dropped from it at an interval of 2 sec. Find the distance between them 1.5sec. after the second stone is released. (g=10m//sec^(2)) .

A ballon is ascending vertically with an acceleration fo 0.2m//s^(2) . Two stones are dropped from it at an interval of 2sec . Find the distance between them 1.5sec after the second stone is released. (use g =9.8 m//s^(2))

Find the modulus of average acceleration (in m/s2) of the block from time t = 2 sec to t = 4 sec.

A lift whose cage is 3 m high is moving up with an acceleration of 2m//s^(2) . A piece of stone is dropped from the top of the cage of the lift when its velocity is 8m/s. if g=10m//s^(2) , then the stone will reach the floor of the lift after

A particle is thrown upward from ground. It experiences a constant resistive force which can produce retardation of 6 m/ sec^2 . What will be the ratio of time of descent to time of ascent (g = 10 m/ sec^2 )

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance S_1 in the first 10 sec and a distance S_2 in the next 10 sec, Then