An air bubble of diameter `2mm` rises steadily through a solution of density `1750kgm^(-3)` at the rate of `0.35cms^(-1)` .Calculate the coefficient of viscosity of the solution (in `Pascal times Sec`).The density of air is negligible. `(g=9.8m/s^(2))`

A gas buble of diameter 2 cm rises steadily at the rate of 2.5 mm s^(-1) through a solution of density 2.25 g cm^(-3) . Calculate the cofficient of viscosity of the lquid. Neglect the density of the gas.

A gas bubble of 2 cm diameter rises through a liquid 1.75 gm cm^(-3) with a fixed speed of 0.35 cm s^(-1) .Naglect the density of the gas. The cofficient of viscosity of the liquid is

An air bubble of 1cm radius is rising at a steady rate of 0.5cms^(-1) through a liquid of density 0.81gcm^(-3) . Calculate the coefficient of viscosity of the liquid. Neglect the density of air. ( Take g=10m//s^(2))

An air bubble of 1 cm radius is rising at a steady rate of 2.00ms^-1 through a liquid of density 1.5gcm^-3 . Neglect density of air. If g=1000cms^-2 , then the coeffieciet of viscosity of the liquid is

An air bubble of 10mm radius is rising at a stready rate of 2mm//sec through a liquid of density 1.47xx10^(8) kg m^(-3) . Calculate the coffe. Of viscosity of liquid (g=9.8 ms^(-2)) neglect density of air.

An air bubble of radius 10^(-2) m is rising up at a steady rate of 2times10^(-3)ms^(-1) through a liquid of density 1.5times10^(3)kgm^(-3) , the coefficient of viscosity neglecting the the density of air, will be (g=10ms^(-2))

An air bubble of radius 1 cm rises with terminal velocity 0.21 cm/s in liquid column. If the density of liquid is 1.47 xx 10^(3) kg//m^(3). Then the value of coefficient of viscosity of liquid ignoring the density of air, will be

An air bubble of diameter 2 cm is allowed to rise through a long cylindrical columu of viscous liquid and travels at the rate of 0.21 cms^(-1) If the density of the liquid is 1.47 g cm^(-3) find the cofficient of vicosity .Given g=9.8ms^(-2) Density of air is to be neglecteed .