`int tsint^(2)dt`

int t/(t+b^2) dt

Integrate the following : int(sin4t+2t)dt

Evaluate indefinite integration. (i) x=intdt " " (ii) int t dt " " (iii) x=int (2t) dt" " (iv) x=int (t^(2)) dt " " (v) x=int (-(2)/(t^3))dt

If f(x)=int_(0)^(x)(dt)/((f(t))^(2)) and int_(0)^(2)(dt)/((f(t))^(2))=(6)^((1)/(3)) then

If f (x) =int _(0)^(g(x))(dt)/(sqrt(1+t ^(3))),g (x) = int _(0)^(cos x ) (1+ sint ) ^(2) dt, then the value of f'((pi)/(2)) is equal to:

If (x)=int_0^x tsint\ dt ,\ then write the value of f^(prime)(x)

if int(e^(t)dt)/(1+t)=a then int e^(t)(dt)/((1+t)^(2))=

The value of int_(0)^(sin^(2)) sin^(-1)sqrt(t)dt+int_(0)^(cos^(2)x)cos^(-1)sqrt(t)dt , is