If `S=0,S'=0` are any two non- concentric circles then its radical axis is

Consider two statements S1 && S2 as s1: Radical Axis is identical to common chord of two circles which are intersecting S2: Radical Axis is locus of all such points such that lengths of tangents drawn from it to two circles are equal

If the circle S=0 touches X -axis then

(a,c) and (b,c) are the centres of two circles whose radical axis is the y-axis.If the radius of the first circle is r then the diameter of the other circle is

STATEMENT-1 : If n circles (n ge 3) , no two circles are non-centric and no three centre are collinear and number of radical centre is equal to number of radical axes, then n = 5. and STATEMENT-2 : If no three centres are collinear and no two circles are concentric, then number of radical centre is ""^(n)C_(3) and number of radical axs is ""^(n)C_(2).

(iii)If two circles cut a third circle orthogonally,then the radical axis of two circle will pass through the center of the third circle.

Let S=0 and S'=0 be two intersecting circles with radii 2 and 3. Their point of intersection areA and B. Let AC and AD be diameter of S=0 and S'=0 respectively.If angle between the circles is theta where cos theta=1/4 then CD equals.

let S_(1)=x^(2)+y^(2)-4x-8y+4=0 and S_(2) be its smage in the line y=x find the equation of circle touching y=x at (1,1) and its radical axes with S_(2) passes through the centre of S_(1)

LOL' and MOM' are two chords of parabola y^(2)=4ax with vertex A passing through a point O on its axis.Prove that the radical axis of the circles described on LL' and MM' as diameters passes though the vertex of the parabola.

r_(1),r_(2) are the radii of two non-intersecting circles having A,B as centres.If P is the centre of AB then the perpendicular distance of P form their radical axis is