The differential equations, find a particular solution satisfying the given condition: `(x^3+x^2+x+1)(dy)/(dx)=2x^2+x ; y=1`when `x = 0`

Explanation

Given , `(x^3+x^2+x+1)(dy)/(dx)=2x^2+x`


`=> (x^2 (x+1) +(x+1)) (dy)/(dx) = x(2x+1)`


`(x^2 +1)(x+1) (dy)/(dx) = x(2x+1)`


`dy = (2x^2+x) / ((x^2+1)(x+1)) dx`


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