Find the general solution of the differential equations `e^xtanydx+(1-e^x)sec^2ydy=0`

Explanation

Given differential equation


`e^xtanydx+(1-e^x)sec^2ydy=0`


`(1-e^x) sec^y dy = -e^x tany dx `


`=> (sec^2y dy) / (tany) = -e^x/(1-e^x) dx`


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