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A cell to emf. E and internal resistance...

A cell to emf. E and internal resistance r supplies currents for the same time t through external resistance`R_1 and R_2` respectively. If the heat produced in both cases is the same, then the internal resistance is given by :

A

`1/r=1/R_1+1/R_2`

B

`r=(R_1+R_2)/2`

C

`r=sqrt(R_1R_2)`

D

`r=R_1+R_2`

Text Solution

AI Generated Solution

To solve the problem, we need to determine the internal resistance \( r \) of a cell supplying current through two different external resistances \( R_1 \) and \( R_2 \), given that the heat produced in both cases is the same. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have a cell with EMF \( E \) and internal resistance \( r \) supplying current through two external resistances \( R_1 \) and \( R_2 \). The heat produced in both cases is the same when the current flows for the same time \( t \). 2. **Using Joule's Law**: ...
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