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A potential difference 100 V is applied ...

A potential difference 100 V is applied across a conductor which is a cylindrical shell of inner and outer diameter 2 cm and 4 cm respectively and length 10 cm. Current flows in a direction parallel to the axis of the conductor. If heat is dissipated in the conductor at the rate 15 W, the resistivity of the material of the conductor is _________ `Omega m`. [Take `pi=22/8`]

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To find the resistivity of the material of the cylindrical conductor, we can follow these steps: ### Step 1: Understand the given parameters - **Inner diameter (D1)** = 2 cm = 0.02 m - **Outer diameter (D2)** = 4 cm = 0.04 m - **Length (L)** = 10 cm = 0.1 m - **Potential difference (V)** = 100 V - **Heat dissipated (H)** = 15 W ...
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