A moving coil galvanometer, having a resistance G, produces full scale deflection when a current `I_g` flows through it. This galvanometer can be converted into [2019]
(i) An ammeter of range 0 to by connecting a shunt resistance`I_0(I_0 gt I_g)` to it and
(ii) Into a voltmeter of range 0 to `V(V=GI_0)` by connecting a series resistance to it. Then,

Options

A. `R_A R_V=G^2 and R_A/R_V=(I_g/(I_0-I_g))^2`
B. `R_A R_V=G^2 and R_A/R_V=(I_g)/((I_0-I_g)) R_A R_V=G^2((Ig)/(I_0-I_g))`
C. `R_A/R_V=((I_0-I_g)/I_g)^2`
D. `R_A/R_V=((I_g/((I_0-I_g))^2 R_A R_V=G^2((I_0-I_g)/I_g)`

Explanation

To solve the problem of converting a moving coil galvanometer into an ammeter and a voltmeter, we will follow these steps:

### Step 1: Understanding the Galvanometer
The moving coil galvanometer has a resistance \( G \) and produces full-scale deflection when a current \( I_g \) flows through it.

### Step 2: Converting to an Ammeter
To convert the galvanometer into an ammeter with a range of \( 0 \) to \( I_0 \) (where \( I_0 > I_g \)), we need to connect a shunt resistance \( R_f \) in parallel with the galvanometer.

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