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In Fig. the velocities are in ground fra...

In Fig. the velocities are in ground frame and the cylinder is performing pure rolling on the plank, velocity of point `'A'` would be

A

`2V_(c)`

B

`2V_(c) + V_(P)`

C

`2V_(c) - V_(P)`

D

`2(V_(c) -V_(p))`

Text Solution

Verified by Experts

The correct Answer is:
C
For pure rollig velocity of the point of contct has to be equal to the velocity of the surface.
let's say cylinder rolls with angular velocity `omega`: At bottom most point,
`V_(C) -omegar = V_(P) rArr omega r = V_(C) - V_(P)`
At top most point
`V_(A) = V_(C) + omega r = 2V_(C) - V_(P)`
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