A chord of a circle is equal to the radius of the circle find the angle subtended by the chord at a point on the monor arc and also at a point on the major arc.

Explanation

Given: `AB` is equal to the radius of the circle.
In `/_\OAB`,
`OA=OB=AB=`radius of the circle.
Thus, `/_\OAB` is an equilateral triangle.
And `/_AOC=60^@`
`/_ACB=1/2/_AOB=1/2xx60^@=30^@`
Since, `ACBD` is a cyclic quadrilateral,
`/_ACB+/_ADB=180^@` [Opposite angles of a cyclic quadrilateral are supplementary]
`=>/_ADB=180^@-30^@=150^@`
`therefore` Angle subtends by the chord at a point on the minor arc and also at a point on the major arc are `150^@` and `30^@`.