If the chord of a circle is equal to the radius of the circle, then the angle subtended by the chord at a point on the minor arc is:

Explanation

Given: `AB` is equal to the radius of the circle.
In `△OAB`,
`OA=OB=AB=`radius of the circle.
Thus, `△OAB` is an equilateral triangle.
And `∠AOC=60^@`
`∠ACB=1/2∠AOB=1/260^@=30^@`
Since, `ACBD` is a cyclic quadrilateral,
`∠ACB+∠ADB=180^@` [Opposite angles of cyclic quadrilateral are supplementary]
`⇒∠ADB=180^@-30^@=150^@`
`therefore` Angle subtends by the chord at a point on the minor arc`=150^@`.